Question

A bag contains 20 discs, which are numbered from 1 to 20. If one disc is drawn at random from the bag,
find the probability that it bears :
(AP - 2018)
a) an even number, b) Prime number, c) Multiple of 5, d) Two digit odd number.​

Answer 1

(a) P(getting an even number) $=\dfrac{1}{2}$

(b) P(getting an prime number) $=\dfrac{2}{5}$

(c) P(getting a multiple of 5) $= \dfrac{1}{5}$

(d) P(getting a two digit odd number) $=\dfrac{1}{4}$

Step-by-step explanation:

Given,

All possible outcomes are:

1,2,3,4, ....., 20

Total number of discs = 20

∴ Total number of all possible outcomes = 20

(a) Favourable outcomes are:

2,4,6,8,.....,20

Number of favourable outcomes = 10

∴ P(getting an even number) = $\dfrac{10}{20}=\dfrac{1}{2}$

(b) Favourable outcomes are:

2, 3, 5, 7, 11,13, 17 and 19

Number of favourable outcomes = 8

∴ P(getting an prime number) =$\dfrac{8}{20}=\dfrac{2}{5}$

(c) Favourable outcomes are:

5, 10, 15 and 20

Number of favourable outcomes = 4

∴ P(getting a multiple of 5) = $\dfrac{4}{20}=\dfrac{1}{5}$

(d) Favourable outcomes are:

11, 13, 15, 17 and 19.

Number of favourable outcomes = 5

∴ P(getting a two digit odd number) = $\dfrac{5}{20}=\dfrac{1}{4}$

Answer 2

Answer:

maybe its 7/10

Step-by-step explanation:

idk why