Question

A bag contains 20 silver balls and x iron balls. If one ball is drawn from the bag, what is the probability that it is: (a) silver (b) iron. If the probability of drawing the silver ball is 1/3times the probability of drawing iron balls, determine the value of x

Answer 1

Answer:

The value of x=60

$\text{P(silver ball)}=\frac{1}{4}$

$\text{P(iron ball)}=\frac{3}{4}$

Step-by-step explanation:

Given : A bag contains 20 silver balls and x iron balls. If one ball is drawn from the bag. If the probability of drawing the silver ball is 1/3 times the probability of drawing iron balls.

To find : What is the probability that it is: (a) silver (b) iron.also determine the value of x

Solution :

Total number of balls = 20+x

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

$\text{P(silver ball)}=\frac{20}{20+x}$

$\text{P(iron ball)}=\frac{x}{20+x}$

We have given that,

$\text{P(silver ball)}=\frac{1}{3}\text{P(iron ball)}$

$\frac{20}{20+x}=\frac{1}{3}(\frac{x}{20+x})$

$20\times 3=x$

$x=60$

So, The value of x=60

Now,

$\text{P(silver ball)}=\frac{20}{20+60}=\frac{20}{80}=\frac{1}{4}$

$\text{P(iron ball)}=\frac{60}{20+60}=\frac{60}{80}=\frac{3}{4}$

Answer 2

Step-by-step explanation:

here it is ...hope u got it . all the very best