A bag contains 20 silver balls and X iron balls. If one ball is drawn from the bag ,what is the probability that it is (1)silver (2)Iron ?If the probability of drawing the Silver balls is one by three times the probability of drawing iron balls, determine the value of x.
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Step-by-step explanation:
P(drawing silver ball) = 20/(20+X)
P(drawing iron ball) = X/(20+X)
Given, 20/(20+X) = X/3(20+X)
=> X = 60
therefore, P(drawing silver ball) = 20/(20+60) = 1/4
P(drawing iron ball) = 60/(20+80) = 3/4
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