Math, asked by mohammadbinshifa, 8 months ago


A bag contains 20 sweets, of which 7 are toffee wrapped in green paper, 6 are mints
wrapped in green
paper, 3 are toffee wrapped in red paper and 4 are mints wrapped in red paper. If a sweet is drawn at
random from the bag, find the probability that the sweet is
(i) a mint wrapped in red paper,
(ii) a toffee,
(iii) wrapped in green paper.​

Answers

Answered by tennetiraj86
1

Answer:

answer for the given problem is given

Attachments:
Answered by saboorarshad2007
0

Answer a) 4/20=2/10=1/5

b)10/20=1/2

c)13/20

Step-by-step explanation: a) Mint wrapped in red paper are 4 and total sweets are 20.

b) toffee wrapped in green paper are 7 and toffee wrapped in red paper are 3 so 7+3=10

c) There are 7 toffee and 6 mints wrapped in green paper so 7+6=13.

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