A bag contains 20 sweets, of which 7 are toffee wrapped in green paper, 6 are mints
wrapped in green
paper, 3 are toffee wrapped in red paper and 4 are mints wrapped in red paper. If a sweet is drawn at
random from the bag, find the probability that the sweet is
(i) a mint wrapped in red paper,
(ii) a toffee,
(iii) wrapped in green paper.
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Answer a) 4/20=2/10=1/5
b)10/20=1/2
c)13/20
Step-by-step explanation: a) Mint wrapped in red paper are 4 and total sweets are 20.
b) toffee wrapped in green paper are 7 and toffee wrapped in red paper are 3 so 7+3=10
c) There are 7 toffee and 6 mints wrapped in green paper so 7+6=13.
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