A bag contains 21 toys numbered 1 to 21. A toy is drawn and then another toy is drawn without replacement. What is the probability that both toys are even numbered?
A 27
B 821
C 314
D 521
E 12
Answers
Answered by
0
Answer:
options are wrong. the answer is 10 toys .
Answered by
6
Answer:
3/14 option c
Explanation:
there are 10 even balls from 1-21
there are 21 numbers from 1-21(including)
probability for 1st ball=(10/21)
probability for 2nd ball=(9/20)
therefore probability=10/21*9/20
=3/14
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