Question

a bag contains 24 balls of which the number of blue ballsis thrice the number of red balls and the number of white ball is twice the number of the red balls. A ball is selected at random what is the probability that is not1: red 2:white​

Answer 1

Answer:

(1)=5/6

(2)=2/3

Step-by-step explanation:

First assume no of red balls =x

Then, no of blue balls =3x

No of white balls=2x

Total no of balls =24

2x+3x+x=24

X=4

No of red balls =4

No of blue balls =12

No of white balls=8

(1)= probability of getting red balls=4/24=1/6

But we have to find probability of not getting red so we subtract it from 1

Hence, probability of not getting red ball=1-1/6=5/6

(2)= similarly, probability of getting white ball=8/24=1/3

Probability of not getting white ball=1-1/3=2/3

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