Question

a bag contains 24 balls of which x are red, 2x are white amd and 3x are blue . A ball selected at random. Find the probability that it is (1) White, (2) not red

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Answer 1

Answer:

Given that, A bag contains total number of balls = 24 A bag contains number of red balls = x A bag contains number of white balls = 2x and a bag contains number of blue balls = 3x By condition, x + 2x + 3x = 24 ⇒ 6x = 24 ⇒ x = 4 ∴ Number of red balls = x = 4 Number of white balls = 2x = 2×4 = 8 and number of blue balls = 3x = 3×4 = 12 So, total number of outcomes for a ball is selected at random in a bag contains 24 balls. ⇒ n(S) = 24 (i) Let E1 = Event of selecting a ball which is not red i.e., can be white or blue. ∴ n(E1) =Number of white balls + Number of blue balls ⇒ ∴ n(E1) = 8 + 12 = 20 (ii) Let E2 Event of selecting a ball which is white n(E2) = Number of white ball = 8 Read more on Sarthaks.com - https://www.sarthaks.com/889163/bag-contains-balls-which-white-are-blue-ball-selected-random-what-the-probability-that-is n(E2)

-------- = 8/24 =1/3

n (s)

Step-by-step explanation:

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Answer 2

$\huge{❥}\:{\mathtt{{\purple{\boxed{\tt{\pink{\red{A}\pink{n}\orange{s}\green{w}\blue{e}\purple{r᭄}}}}}}}}❥$

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