Question

A bag contains 25 paisa and 50 paisa coins whose total value is ₹30.if the number of 25 paisa coins is four times that of 50 paisa coins, find the number of each type of coins.

Answer 1

let the number of 50 paisa coin be x
hence number of 25 paisa coin= 4x 
total value of 50 paisa coins= Rs. 0.50x
And, the value of 25 paisa coins= Rs. x [∵4x*0.25= x]

∴total value of coins in bag= x+0.50x=1.50x
but, total value provided= Rs. 30

∴30=1.50x
⇒x=20

number of 50 paisa coins=20 and number of 25 paisa coins=4*20=80

Answer 2

Hello Friend !

The answer is given below :

Let the 25 paisa coins be x and 50 paisa coins be y

Then according to question , 25 paisa coins is four times than that of 50 paisa coins.

⇒ x = 4y ..............(equation 1)

Since 1 Rs = 100 paisa.

⇒ total number of 25 paisa coins can be written as $\frac{25}{100} x$ 

⇒ i.e., = $\frac{1}{4} x$ Rs

Similarly total number of 50 paisa coins can be written as $\frac{50}{100}y$

⇒ i.e., = $\frac{1}{2} y$

Also, $\frac{1}{4} x$ + $\frac{1}{2} y$  = 30 Rs .........................(equation 2)  
 
Since x = 4y    [From equation 1]

Therefore substituting x in equation 2, we get

⇒ $\frac{1}{4} * 4y$ + $\frac{1}{2}y$ = 30 

⇒ 2y + y = 60 

⇒ 3y = 60

⇒ y = 20

Therefore number of 50 paisa coins are 20

And number of 25 paisa coins are x = 4y = 4*20 = 80

This is your answer.

Hope this helps !