A bag contains 25 paisa and 50-paisa coins whose total value is ₹ 30. If the number of
25-paisa coins is four times that of 50-Paisa coins, find the number of each type of coins.
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1
Answer:
let the 50paise be x and 25paise be 4x
50*x+25*4x=3000
50x+100x=3000
150x=3000
x=20,then
total coins of 25 is 20*4=80
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Let us assume that
Number of 25p coins = 8x
Number of 50p coins = 4x
Number of Rs. 1 coins = 2x
As per the given condition
8x + 4x + 2x = 840
14x = 840
x = 840/14
x = 60
Hence,
Amount of 25p coin = 60 × 8 × 25 = 12000 paisa = Rs. 120
Amount of 50p coin = 60 × 4 × 50 = 12000 paisa = Rs. 120
Amount of Rs. 1 coin = 60 × 2 × 1 = Rs. 120
On summing up the above-obtained values the total amount in the bag is Rs120+Rs120 +Rs 120 = Rs360
Number of 25p coins = 8x
Number of 50p coins = 4x
Number of Rs. 1 coins = 2x
As per the given condition
8x + 4x + 2x = 840
14x = 840
x = 840/14
x = 60
Hence,
Amount of 25p coin = 60 × 8 × 25 = 12000 paisa = Rs. 120
Amount of 50p coin = 60 × 4 × 50 = 12000 paisa = Rs. 120
Amount of Rs. 1 coin = 60 × 2 × 1 = Rs. 120
On summing up the above-obtained values the total amount in the bag is Rs120+Rs120 +Rs 120 = Rs360
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