A bag contains 25 paise, 10 paise and 5 paise coins in the ratio 1 : 2 : 3. If their total value is 760, the number of 5 paise coins is
(a) 10
(b) 50
(c) 30
(d) 40
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Answer:
Let the Number of 25 paisa coins = x
therefore , Number of 10 paisa coins = 2x
and Number of 5 paisa coins = 3x
Hence Total Value = 25*x + 10*2x +5*3x
=25x+20x+15x = 60x ------ (1)
According to Question ,
total Value = 760 -------------------- (2)
from 1 and 2 , we get
60x = 760
or x =76/6
Hence , Number of 5 Paisa Coins = 3x = 3*76/6 = 76/2 = 38
Hope this helps you!!
Thank You..
Cheers!!!!
Let the Number of 25 paisa coins = x
therefore , Number of 10 paisa coins = 2x
and Number of 5 paisa coins = 3x
Hence Total Value = 25*x + 10*2x +5*3x
=25x+20x+15x = 60x ------ (1)
According to Question ,
total Value = 760 -------------------- (2)
from 1 and 2 , we get
60x = 760
or x =76/6
Hence , Number of 5 Paisa Coins = 3x = 3*76/6 = 76/2 = 38
Hope this helps you!!
Thank You..
Cheers!!!!
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