A bag contains 25 paise, 50 paise and rs.1 coins. There are 220 coins in all and the total amount in the bag is rs.160. If there are thrice as many rs.1 coins as there are 25 paise coins, then what is the number of 50 paise coins? *
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Let there are X one rupee's coin, Y 50 paise's coins and Z 25 paise's coins.
Now,
X +Y +Z = 220 ---------------- (1)
Total amount = Rs. 160
Now,
X + (Y/2) + (Z/4) = 160
4X +2Y +Z = 640 ---------------- (2)
Thrice as many 1 Re coins as 25 paise,
X = 3Z -------- (3)
On Solving equations 1, 2 and 3,
Z = 40
X = 3*40 = 120
Y = 220 - (120+40)= 60
50 paise's coins = 60.
Now,
X +Y +Z = 220 ---------------- (1)
Total amount = Rs. 160
Now,
X + (Y/2) + (Z/4) = 160
4X +2Y +Z = 640 ---------------- (2)
Thrice as many 1 Re coins as 25 paise,
X = 3Z -------- (3)
On Solving equations 1, 2 and 3,
Z = 40
X = 3*40 = 120
Y = 220 - (120+40)= 60
50 paise's coins = 60.
VaibPiyu:
This is a bit tough method than using 1 variable
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0
Answer:
56777
Step-by-step explanation:
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