Question

A bag contains 25 paise and 50 paise coins whose total value is Rs 30. If the number of 25 paise coins is four times that of 50 paise coins, find the number of each type of coins

Answer 1

Answer:

No.of 25 paise coins=80.

No.of 50 paise coins=20.

Step-by-step explanation:

Let the no. of 50 paise coins be x.

So, A.T.Q. no. of 25 paise coins will be 4x.

Total Value of Coins=Value of 50 paise coins + value of 25 paise coins.

Total Value of Coins= Rs.30. (Given)

Value of 50 paise coins= 50x.

Value of 25 paise coins= 25(4x)= 100x.

Now, Rs.30=30×100paise=3000 paise.

3000=50x+100x.

3000=150x.

x=3000/150

x=20.

Hence, the no. of 50 paise coins=x=20.

& the no.of 25paise coins=4x=4×20=80.

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Answer 2

${\large{\underbrace{\sf{\purple{Required \ Answer}}}}}$

☯️ Let the number of 50 pαise coins = x

So, the money vαlue contribution of 50 pαise coins in bαg = 0.5x.

The number of 25 pαise coins in bαg = 4x

The money vαlue contribution of 25 pαise coins in bαg = 0.25 (4x) = x.

${\large{\underbrace{\frak{\purple{According \ to \ the \ question,}}}}}$

$\longrightarrow$ 0.5x + x = 30

$\longrightarrow$ 1.5x = 30

Dividing both sides by 1.5, we get

$\longrightarrow$ 1.5x/1.5= 30/1.5

$\longrightarrow$ x = 20

$\therefore$ The number of 50 pαise coins = x = 20,

The number of 25 pαise coins = 4x = 4 (20) = 80.

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