A bag contains 25 paise and 50bpaise coins whose total value is RS 30.If the number of 25 paise coins is four times that of 50 paise coins , find the the number of each tupe of coins?
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let x be number of 25 paisa coins and
y be number of 50 paisa coins
By data, 4x=y
We know that 50 paise =2×25 paise
so 4x=2y
So ratio is value of 25 paisa coin and 50 paisa coin is 2:1
30÷3=10
Value of 25 paisa coins is 20 ruppess
value of 50 paisa coins is 10 ruppess
1ruppe=100 paisa
So number of 25 paisa coins is given by 4×20=80
number of 50 paisa coins is 2×10= 20
y be number of 50 paisa coins
By data, 4x=y
We know that 50 paise =2×25 paise
so 4x=2y
So ratio is value of 25 paisa coin and 50 paisa coin is 2:1
30÷3=10
Value of 25 paisa coins is 20 ruppess
value of 50 paisa coins is 10 ruppess
1ruppe=100 paisa
So number of 25 paisa coins is given by 4×20=80
number of 50 paisa coins is 2×10= 20
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