A bag contains 25 paise coins, 50 paise coins and 1 rupee coins whoose values are in the ratio of 8:4:2. the total values of coins are 840. Then find the total number of coins.
Answers
QUESTION :-
A bag contains 25 paise coins, 50 paise coins and 1 rupee coins whoose values are in the ratio of 8:4:2. the total values of coins are 840. Then find the total number of coins.
SOLUTION :-
Given,
=> In a bag 25 paise coins, 50 paise coins, and 1 rupee coins whose values are in the ratio of 8:4:2. the total values of coins are 840.
=>We need to find the total number of coins.
Now,
=>Let us assume that
=>Number of 25p coins = 8x
=>Number of 50p coins = 4x
=>Number of Rs. 1 coins = 2x
=>As per the given condition,
=>8x + 4x + 2x = 840
=>14x = 840
=>x = 840/14
=> .°. x = 60
Hence,
=> Amount of 25p coin = 60 × 8 × 25 = 12000 paisa = Rs. 120
=> Amount of 50p coin = 60 × 4 × 50 = 12000 paisa = Rs. 120
=> Amount of Rs. 1 coin = 60 × 2 × 1 = Rs. 120
=> On summing up the above-obtained values the total amount in the bag is Rs120+Rs120 +Rs 120 = Rs360.
Step-by-step explanation:
let the ratio of the 25 paise , 50 paise and 1 rupee coin be expressed as
8x , 4x , 2x. respectively
so,
value of 25 paise = 8x × 25paise
8x × .25 = 2x
similarly value of 50 paise = 4x × 50 paise
4x × .50 = 2x
value of 1 rupee coin = 2x × 1 rupee = 2x
therefore
value of 25paise + value of 50 p + value of 1 rupee = 840
2x + 2x + 2x = 840
6x = 840
x = 840/6
x = 140
therefore
number of 25 paise coin = 8 × 140 = 1120
number of 50 paise coin = 4 × 140 = 560
number of 1 rupee coin = 2 × 140 = 280
total coins = 1120 + 560 + 280 = 1960