A bag contains 25 paise coins, 50 paise coins and 1 rupee coins whoose values are in the ratio of 8:4:2. the total values of coins are 840. Then find the total number of coins.
Answers
Given
In a bag 25 paise coins, 50 paise coins, and 1 rupee coins whose values are in the ratio of 8:4:2. the total values of coins are 840.
We need to find the total number of coins.
Solution
Let us assume that
Number of 25p coins = 8x
Number of 50p coins = 4x
Number of Rs. 1 coins = 2x
As per the given condition
8x + 4x + 2x = 840
14x = 840
x = 840/14
x = 60
Hence,
Amount of 25p coin = 60 × 8 × 25 = 12000 paisa = Rs. 120
Amount of 50p coin = 60 × 4 × 50 = 12000 paisa = Rs. 120
Amount of Rs. 1 coin = 60 × 2 × 1 = Rs. 120
On summing up the above-obtained values the total amount in the bag is Rs120+Rs120 +Rs 120 = Rs360
Answer:
In a bag 25 paise coins, 50 paise coins, and 1 rupee coins whose values are in the ratio of 8:4:2. the total values of coins are 840.
We need to find the total number of coins.
Solution
Let us assume that
Number of 25p coins = 8x
Number of 50p coins = 4x
Number of Rs. 1 coins = 2x
As per the given condition
8x + 4x + 2x = 840
14x = 840
x = 840/14
x = 60
Hence,
Amount of 25p coin = 60 × 8 × 25 = 12000 paisa = Rs. 120
Amount of 50p coin = 60 × 4 × 50 = 12000 paisa = Rs. 120
Amount of Rs. 1 coin = 60 × 2 × 1 = Rs. 120
On summing up the above-obtained values the total amount in the bag is Rs120+Rs120 +Rs 120 = Rs360