Question

a bag contains 25p coins,50p coins and 1rs coins whose values are in the ratio 8:4:2 he total values of coins are 840 ​

Answer 1

Correct Question:

A bag contains 25p coins, 50p coins and 1rs coins whose values are in the ratio 8:4:2 he total values of coins are 840 . Find the number of each type of coin.

Solution:

Given ratio = 8:4:2

Total Number of coins in bag = 840

Each type of coin = 25 p, 50 p and 1 rs

Let number 25p coins be 8x

Number of 50p coins be 4x

number of 1rs coins be 2x

=> 8x + 4x + 2x = 840

=> 14x = 840

=> x = 840/14

=> x = 60

★ Number of 25p coins:

=> 8x

=> 8 × 60

=> 480

★ Number of 50p coins:

=> 4x

=> 4 × 60

=> 240

★Number of 1rs coins:

=> 2x

=> 2 × 60

=> 120

Answer 2

Answer:

Step-by-step explanation:

Let the common multiple of the given ratio be x

There for Number of 25p will be 8x

Number of 50p will be 4x

And Number of 1 rupee will be 2x

Now in given question total amount is Rs 840

Therefore, 25*8x+50*4x+100*2x=84000

Here I have converted the money in paisa

200x+200x+200x=84000

X=14

Total number of coins is 14*3=42