Question

A bag contains 25paise and 50 paise coins whose total value is Rs 30. If the number of 25 paise coins is four times that of 50 paise coins, find the number of each type of coins.

Answer 1

Answer:

Total amount in the bag = Rs. 30=3000 paise

Let the number of 50 paise coins be x

Then the number of 25 paise coins =4x

Now, according to the question

25(4x)+50x=3000

100x+50x=3000

150x=3000

x=

150

3000

x=20

4x=80

Therefore, number of 50 paise coins =20

Number of 25 paise coins =80

Answer 2

$\large \sf\underline{ \underline{ \red{given : }}} \:$

• Total amount = 30Rs.

• Number of 25paise coins is 4 times number of 50paisa coins.

$\\ \\ \large \sf\underline{ \underline{ \red{to \: find: }}}$

• Number of 25paisa and 50paisa coins.

$\\ \\ \large \sf\underline{ \underline{ \red{to \: know : }}}$

• 1 Rupees = 100 paisa

$\\ \\ \large \sf\underline{ \underline{ \red{solution : }}} \:$

➥ Let number of 50paisa coins = x

• Amount of 50paisa coins = 50(x)

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➥ Number of 25paisa coins = 4x

• Amount of 25paisa coins = 25(4x)

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We know , total amount is 30Rs = (30×100)paisa

• So, total amount = 3000paisa.

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➣ 3000 = 50x + 25(4x)

➣ 3000 = 50x + 100x

➣ 3000 = 150x

➣ x = 3000/150

➣ x = 20

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Number of 50paisa coins = x = 20

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Number of 25 paisa coins = 4x = 4(20) = 80

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Hence , there are 20 coins of 50paisa and 80coins of 25paisa in the bag.