Question

A Bag Contains (2n+1) coins. It's known that (n+1) of these have a head on both sides whereas the rest are fair. A coin is picked at random from the bag & tossed. If the probability that toss results in a head is 31/92 determine the value of n

Answer 1

Answer:

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( 6289888928)

Step-by-step explanation:

Answer 2

Answer:

2n+1= total coins

there can be two cases

Case I - choosing biased coin

P(B)=

2n+1

n

Case II = choosing unbiased coin

P(UB)=

2n+1

n+1

P(Head)=

2n+1

n

×1+

2n+1

n+1

×

2

1

=

2(2n+1)

2n+(n+1)

=

2(2n+1)

3n+1

⇒

2n+1

3n+1

=

42

62

⇒(3n+1)42=(2n+1)62

126n+42=124n+62

2n=62−42

2n=20

⇒n=10