Question

A bag contains 3 apples and 5 oranges and another bag contains 4 apples and 4 oranges, what is the probability that a fruit selected at random

Answer 1

3
$3 + 4y \geqslant \geqslant 45 - 45 >$

Answer 2

Given:

Bag 1 contains 3 apples and 5 oranges.

Bag 2 contains 4 apples and 4 oranges.

To find:

The probability of selecting a fruit randomly.

Step-by-step explanation:

Step 1 of 1

BAG 1:

Bag 1 contains 3 apples and 5 oranges.

The total number of fruits in it are 8.

The probability of selecting a fruit randomly from bag 1 will be:

$P(1)=\frac{1}{8}$

BAG 2:

Bag 2 contains 4 apples and 4 oranges.

The total number of fruits in it are 8.

The probability of selecting a fruit randomly from bag 2 will be:

$P(2)=\frac{1}{8}$

Therefore, the probability that a fruit is selected at random is:

$P(1)+P(2)=\frac{1}{8} +\frac{1}{8}=\frac{2}{8} \\=\frac{1}{4}$