Question

A bag contains 3 black counters, 4 red counters and 5 blue counters. A counter is taken at random down the probability that it is a black or red counter.

Answer 1

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Answer Red counter

Answer 2

Answer:

Total number of counters = 12

P(getting red or black counter) = P(getting red)×P(getting black)

= (4/12)×(3/12) = 1/12