Question

A bag contains 3 green and 7 white balls. Two balls are drawn from the bag in succession without replacement. What is the probability that both were white?

Answer 1

Answer:

2/10 is the probability of getting 2white balls from the bag

Answer 2

Answer:

The probability that both were white is $\frac{7}{15}$

Step-by-step explanation:

Given : A bag contains 3 green and 7 white balls. Two balls are drawn from the bag in succession without replacement.

To find : What is the probability that both were white?

Solution :

Number of green balls = 3

Number of white balls = 7

Total number of balls are 3+7=10

Two balls are drawn from the bag in succession without replacement.

Probability of getting first ball is white is $\frac{7}{10}$

Probability of getting second ball is white is $\frac{6}{9}$

So, The probability that both were white is given by

$P=\frac{7}{10}\times \frac{6}{9}$

$P=\frac{7}{15}$

Therefore, The probability that both were white is $\frac{7}{15}$