Question

A bag contains 3 green and 8 white balls. If one ball is drawn from it at random, find the chance that the ball drawn is green

Answer 1

Answer:

3 / 11

Step-by-step explanation:

P(green) = ( # green balls ) / ( # balls )

             = 3 / ( 3 + 8 )

             = 3 / 11

Answer 2

Green Ball=3

White Ball=8

Total Ball=3+8=11

$\boxed{\mathtt{Probability=\frac{Favourable\: Outcomes}{Total\: Outcomes}}}$

If Green Ball is Chosen

Total Green Ball=3

Total Ball=11

$\boxed{\mathtt{\huge{P(green)=\frac{3}{11}}}}$