Question

A bag contains 3 green balls,1 blue ball and 1 red ball what is the probability of getting a green ball and a non green ball

Answer 1

Step-by-step explanation:

P( getting a green ball) = 3/5

P( getting a non - green ball) = 2/5.

Here, '/' means Upon!

Answer 2

Given :

• Number of green balls = 3
• Number of blue balls = 1
• Number of red balls = 1

To Find :

• Probability of getting a green ball
• Probability of getting non-green balls

Formula used :

$Probability = \dfrac{number \: of \: events}{total \: number \: of \: outcomes}$

Solution :

Number of green balls = 3

Total number of balls = (no.of red balls +green balls+blue balls) = 3+1+1 = 5

Then according to the question,

$Probability (getting \: green \: balls) = \dfrac{number \: of \: green \: balls}{total \: number \: of \: balls} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3}{5}$

And,

Number of non-green balls = 1 + 1 = 2

Total number of balls = 5

$Probability (getting \: non \: green \: balls) = \dfrac{number \: of \: non \: green \: balls}{total \: number \: of \: balls} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2}{5}$

Therefore, the probability of getting green balls is 3/5 and the probability of getting non-green balls is 2/5.