Question

A bag contains 3 red, 4 white and 5 blue balls. Al balls are different. Two balls are
drawn at random. What is the probability that they are of different colour?
​

Answer 1

Answer:

Total number of bassl =3+4+5=12

Favourable number of cases are total minus the balls drawn from same colour

12C

2−(3C2+ 4C 2+5C2)

=66−(3+6+10)=66−19=47

Total number of cases = 12C 2

=66

Hence the required probability

=

Totalnumberofcases

Favourablecases

=

66

47