A bag contains 3 red, 4 white and 5 blue balls. Al balls are different. Two balls are
drawn at random. What is the probability that they are of different colour?
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Answer:
Total number of bassl =3+4+5=12
Favourable number of cases are total minus the balls drawn from same colour
12C
2−(3C2+ 4C 2+5C2)
=66−(3+6+10)=66−19=47
Total number of cases = 12C 2
=66
Hence the required probability
=
Totalnumberofcases
Favourablecases
=
66
47
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