A bag contains 3 red, 4 white and 5 blue balls. All balls are different. Two balls are
drawn at random. What is the probability that they are of different colour?
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Step-by-step explanation:
Total number of bassl =3+4+5=12
Favourable number of cases are total minus the balls drawn from same colour
12
C
2
−(
3
C
2
+
4
C
2
+
5
C
2
)
=66−(3+6+10)=66−19=47
Total number of cases =
12
C
2
=66
Hence the required probability
=
Totalnumberofcases
Favourablecases
=
66
47
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