Question

A bag contains 3 red, 5 black and 7 white balls . A ball is drawn from the bag at random . what is the probability that the ball drawn is
1. white.
2. red.
3. non red.
4. red or white​

Answer 1

Answer:

1. 7/15
2. 3/15
3. 12/15
4. 10/15

Step-by-step explanation:

no.of red balls-3

white balls-7

black balls-5

1. probability of getting white ball = no. of white balls / total no. of balls in the bag= 7/15
2. probability of getting red ball = no.of red balls / total no.of
3. probability of getting non red ball = no. of white balls +no.of black balls / total no of balls =7+5/15=12/15
4. probability of getting red or white ball = no. of red balls + white balls / total no.of balls= 3+7/15=10/15

Answer 2

Answer:       1.    $\frac{7}{15}$

                    2.    $\frac{1}{5}$

                    3.    $\frac{4}{5}$

                    4.    $\frac{2}{3}$

Step-by-step explanation:

Total no.of balls => 3 + 5 + 7 = 15

No. of white ball => 7 = n (W)

No. of red ball => 3 = n (R)

No. of non-red ball => 5 + 7 =>  12 = n (NR)

No. of red or white ball => 3 + 7 =>  10 = n (RW)

  PROBABILITY =     NO.  OF  FAVOURABLE   OUTCOMES

                                          TOTAL  NO.  OF  OUTCOMES

The probability that the drawn ball is  :-

1.   P (W) =  $\frac{7}{15}$

   

    2.    P (R)  =   $\frac{3}{15}$   =>   $\frac{1}{5}$

   

    3.    P (NR)  =   $\frac{12}{15}$   =>   $\frac{4}{5}$

    4.    P (RW)  =   $\frac{10}{15}$   =>   $\frac{2}{3}$