Question

A bag contains 3 red,5 blue,and 6 white marbles,A marble is drawn at random from the bag.what is the probability of getting: 1) a red marble. 2) a blue marble. 3) a non white marbled​

Answer 1

Step-by-step explanation:

1) p(red)= 3/(3+5+6) = 3/ 14

2) p(blue) = 5/14

3) p(white) = 6/14

p(non white)= 1-p(white) = 1- 6/14 = 8/14 = 4/7

Answer 2

Answer:

Here, number of red marbles= 3

Number of blue marbles = 5

Number of white marbles= 6

∴ Total number of marbles = 3 + 5 + 6 = 14

Probability of event = $\frac{Number of favorable outcomes}{Total number of outcomes}$

1) Probability of getting red marble = $\frac{3}{14}$

2) Probability of getting blue marble = $\frac{5}{14}$

3) Probability of getting non-white marble = $\frac{3+5}{14}$ = $\frac{8}{14}$ = $\frac{4}{7}$

Hope it helps :)