Question

A bag contains 3 red,5yellow and 4 green balls.3 balls are drawn randomly, what is the probability that the ball drawn contains no yellow ball?

Answer 1

the probability of a possible event is =the no. of favourable outcomes /total no. of possible outcomes.

so, the probability for this is, 3/12=1/4

Answer 2

The answer is 7/ 12 as there are 12 balls in all and the sum of the red and green balls is 7 therefore 7/12