Question

A bag contains 3 red 6 white and 7 blue balls. If two balls are drwan at random without replacement, then the probability of getting both white balls is

Answer 1

Answer:

1/8

Step-by-step explanation:

Total number of balls = 3 + 6 + 7 = 16.

Probability of getting white ball first time = 6c₁/16c₁. = 6/16.

Now there are 5 white balls as we are not replacing the previously drawn ball. Total number of balls = 3 + 5 + 7 = 15.

Probability of getting white ball second time = 5c₁/15c₁ = 5/15

Thus probability both balls are white = 6/16 * 5/15 = 1/8.