Question

A bag contains 3 red, & 6 white, 4 blue and 7 yellow balls. a ball is drawn. what is
the probability that the ball will be either white on yellow ? plz details explanation​

Answer 1

Answer:

If the first drawn ball is White & second is Blue then;

P (event 1) = 6/16 * 7/15 = 7/40

If the first drawn ball is Blue & second is White then;

P (event 2) = 7/16 * 6/15 = 7/40

P (White & Blue) = P (event 1) + P (event 2) = 7/40 + 7/40 = 7/20 = 0.35