Question

A bag contains 3 red and 5 green sweets. tim takes a sweet at random and eats it, he then takes another sweet. find the probability that tim takes 2 red sweets

Answer 1

No.of red sweets = 3

No.of green sweets = 5

Total no.of sweets = 3+5 = 8

P(E) = Favourable outcomes/ Total no.of outcomes

P(red sweet) = 2/8 = 1/4 or 0.25