Question

A bag contains 3 red balls, 4. blue balls and 6 green ball. A ball is drawn randomly. Find the probability of getting a blue ball.​

Answer 1

Answer:

Probability of getting the blue ball=n(A)/p(a)

13/6

Answer 2

Answer: 7/13

Step-by-step explanation:

Total no. of balls=4+6+3=13

Total no. of ways one ball out of 7,n(S)=13C 1

No.of ways of drawing 1 ball,none of then is blue,n(E)=13−6=7C 1

probability=  

n(S)/n(E) = 7/13

​