Question

A bag contains 3 red balls ,4 blue balls and 9 green balls. Mary draws 1 ball out of bag . What is the probability that she gets a green balls and blue balls​

Answer 1

Total Balls = n(S) = 3+4+9= 16

1) No. of green ball = n(A) = 9

$probability = \frac{n(a)}{n(s)}$

$= \frac{9}{16} = \frac{3}{4}$

2) No. of blue ball = n(B) = 4

$probability = \frac{n(b)}{n(s)}$

$= \frac{4}{16} = \frac{1}{4}$

I hope this is your answer.

Thank You.

Answer 2

Answer:

1/4-Blue

1/9-Green

Step-by-step explanation:

Total no. of green balls =9

Balls Mary draws out of the bag=1

Probability=1/9

Total no. of blue balls=4

Balls Mary draws out of the bag=1

Probability=1/4

HOPE IT HELPS