Question

A bag contains 3 red balls, 5 white balls and 7 black balls. The probability that a ball drawn from the bag at random will be neither red nor black is

Answer 1

The probability that a ball drawn from the bag at random will be neither red nor black is $\frac{1}{3}$

Solution:

The probability of an event is given as:

$Probability = \frac{\text{ number of favorable outcomes }}{\text{ total number of possible outcomes }}$

Given that,

A bag contains 3 red balls, 5 white balls and 7 black balls

Total number of possible outcomes = 3 + 5 + 7 = 15

Favorable outcomes = ball drawn from the bag at random will be neither red nor black

Which means, ball drawn must not be red or black

Therefore,

Favorable outcome = 5 white ball

$Probability = \frac{5}{15}\\\\Probability = \frac{1}{3}$

Thus the probability that a ball drawn from the bag at random will be neither red nor black is $\frac{1}{3}$

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