A bag contains 3 red balls , 5 white balls and 8 blue balls. one ball is taken out of the bag at random. find the probability that the ball taken out (a) red ball (b) not a white ball.Answer
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Answered by
0
Answer:
(a)3/16. (b) 11/16
Step-by-step explanation:
first total no . of balls = 3+5+8 = 16
(a) red balls
= 3/16
(b) not white balls
means 3+8 = 11
= 11/16
Answered by
0
Answer:
Total no. of balls:-
5+3+8=16 balls
a)a red ball
p(a red ball)= no. of red balls/total no. of balls
=3/16
b)not a white ball= sum of red and blue balls/total no. of balls
=3+5/16
= 8/16
= 1/2
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