Question

A bag contains '3' red balls and 4 black balls. A ball is selected at
random from the bag, what is the probability that the ball selected
1) Black 2) Red
​

Answer 1

Answer:

1)4/7

2) 3/7

since probability is

=>possible outcomes/total no of observations

so in case of black its 4 balls so 4/7

and in case of red its 3/7 =) hope it helped you =)

Answer 2

Answer:

S={1R,2R,3R,1B,2B,3B}

n(s)=6

A={1B,2B,3B}

n(a)=3

P(A)=n(a)/n(s)

=6/3=1/2

B={1R,2R,3R}

n(b)=3

p(b)=n(b)/n(s)

=6/3=1/2