Question

A bag contains 3' red balls and 4 black balls. A ball is selected at
random from the bag, what is the probability that the ball selected
1) Black 2) Red
​

Answer 1

Answer:

number of red balls=3

number of black balls=4

total number of balls=3+4=7

1)probability of getting black ball=4/7

2)probability of getting red ball=3/7

Answer 2

Step-by-step explanation:

N(S) = {3+4}={7}

1) P(B) = n(B)/N(S)

= 4/7

2) P(R) = n(R)/N(S)

= 3/7

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