Question

A bag contains 3 red balls and 5 black
balls. A ball is drawn at random from
the bag what is the probability that
the ball drawn (i) red (ii) not red?​

Answer 1

Answer:

PROBABILITY OF RED BALLS=3/8

AND SECOND ONE=0/8

Step-by-step explanation:

Answer 2

No. of red balls = 3

No. of black balls= 5

Total no. of balls = 8

(i) Probability of getting a red ball = $\small\sf\frac{3}{8}$

(ii) Probability of not getting a red ball = 1 - P(E)

= 1- $\large\sf\frac{3}{8}$

= $\large\sf\frac{5}{8}$