Question

A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?

Answer 1

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Answer 2

Given:

• Total number of balls containing in the bag = 3 red balls + 5 black balls
• A ball is drawn at random from the bag.

To Find:

• Probability that the ball drawn is red.
• Probability that the ball drawn is not red.

Solution:

According to the question,

Given, the total number of balls = No. of red balls + No. of black balls

So, the total no. of balls = 5 + 3 = 8

We know that,

The probability of an event is the ratio between the no. of favourable outcomes and the total number of outcomes.

$:\implies P(E)=\frac{Number \ of \ red \ balls}{Total \ number \ of \ balls}$

Therefore, solution for your first question,

Probability of drawing red balls = P (red balls) = $\frac{Number \: of \: red \: balls }{Total \:number \: of \: red \: balls} = \frac{3}{8}$

$:\implies \boxed {\underline{\underline{\frac{3}{8} }}}$

Solution for your second question,

Probability of drawing black balls = P (black balls) = $\frac{Number \: of \: black \: balls }{Total \:number \: of \: black \: balls} = \frac{5}{8}$

$:\implies \boxed {\underline{\underline{\frac{5}{8} }}}$