Question

a bag contains 3 red balls and 5 black balls a ball is drone at random from the bag what is the probability that the ball drawn A red? B not red ​

Answer 1

${\huge{\star{\underline{\underline{\mathtt{\green{QuestioN}}}}}}}{\huge{\star}}$

✳A bag contains 3 red balls and 5 black balls a ball is drone at random from the bag. What is the probability that the ball drawn A red? B not red?

$\huge\underline\mathbb{\red♡A\pink{N}\green{S}\blue{W}\purple{E}\orange{R:}}$

➡Total number of the balls are= 3(red)+5(black)=8

➡Let E = event of drawing 1 red ball.

➡Here, number of red blls= 3

(A) Probability =$\frac{possible\:outcomes}{total\:outcomes}$

P(E)= (of drawing a red ball) = $\frac{3}{8}$

(B) probabailty (of not drawing a red ball)

1 - p(drawing a red ball)

1 - $\frac{3}{8}$

=$\frac{5}{8}$

✴(A) = $\frac{3}{8}$

✳(B) =$\frac{5}{8}$

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$\large\red{\underline{{\boxed{\textsf{Thank\:you}}}}}$

Answer 2

$\sf\blue\bigstar$Total number of the balls are= 3(red)+5(black)=8

$\sf\blue\bigstar$Let E = event of drawing 1 red ball.

$\sf\blue\bigstar$Here, number of red blls= 3

$\sf\blue\bigstar$(A) Probability=$\huge\frac{possible\:out\:comes}{total\:out\:comes}$

$\sf\blue\bigstar$Total out comes possible out comes

$\sf\blue\bigstar$P(E)= (of drawing a red ball) =$\huge\frac{3}{8}$

$\sf\blue\bigstar$B probabailty (of not drawing a red ball)

$\sf\blue\bigstar$1 - p(drawing a red ball)

$\sf\blue\bigstar$1 -$\huge\frac{3}{8}$

=$\huge\frac{5}{8}$

$\sf\blue\bigstar$A= $\huge\frac{3}{8}$

$\sf\blue\bigstar$B=$\huge\frac{5}{8}$