A bag contains 3 red beads and 7 green beads. Another contain one red and one green more. The probability of getting a red from which bag is more.?
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Answered by
40
Answer:
Case I
Total no. if outcomes = 3 + 7 = 10
No. of favourable outcomes (red) = 3
P(E) = 3/10 = 0.3
Case II
Total no. of outcomes = (3 + 1) + (7 + 1) = 12
No. of favourable outcomes (red) = 3 + 1 = 4
P(E) = 4/12 = 1/3 = 0.333
The probability in both cases is almost same but is greater in second case..
itzDopeGirl ❤️
Answered by
12
Answer:
Case I
Total no. if outcomes = 3 + 7 = 10
No. of favourable outcomes (red) = 3
P(E) = 3/10 = 0.3
Case II
Total no. of outcomes = (3 + 1) + (7 + 1) = 12
No. of favourable outcomes (red) = 3 + 1 = 4
P(E) = 4/12 = 1/3 = 0.333
The probability in both cases is almost same but is greater in second case..
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