A bag contains 3 red marbles and 4 blue marbles. then, 2 marbles are drawn from the bag, at random, without replacement. if the first marble drawn is red, what is the probability that the second marble is blue?
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Answer:
4/9 or 40%
Step-by-step explanation:
3+4= 9 marbles total
blue marbles: 4
4 blue marbles out of 9 marbles, so
4/9
Percentage:
4 divided by 9
4/9
=0.444444
0.44444 rounds to -> 0.4
0.4= 40/100
40/100
=40%
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