A bag contains 3 white, 5 black and 2 red balls. If a ball is drawn at random, find the probability that the ball drawn is, (i) a black ball (ii)a red ball (iii) a white ball (iv) not a black ball.
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Answered by
1
Answer:
Step-by-step explanation:
total no. of outcomes = 10
(i)no. of favourable outcomes = 5
P(of getting a black ball) = 5/10 = 1/2
(ii)no. of favourable outcomes = 2
P(of getting a red ball) = 2/10 = 1/5
(iii) no. of favourable outcomes = 3
P(of getting a white ball) =3/10
(iv)no. of favourable outcomes = 3+2 =5
P(of not getting a black ball) = 5/10=1/2
OR
(iv) P(of not getting a black ball) = 1 - P(of getting a black ball)
= 1- 1/2
=1/2
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Answered by
0
Answer:
I) 0.5
ii) 0.3
iii) 0.5.
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