A bag contains 3 white balls, 5 redballs and 4 blue balls. A ball is drawn at random from the bag.What is the probability that the ball drawn is of the following type. (I) Blue (ii) White. (iii) Red. (iv) Not White
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Answered by
0
Answer:
red ball 11/18
not white 1/2
blue 17/18
Answered by
1
Answer:
PROBABILITY OF AN EVENT = NO... OF FAVOURABLE OUTCOMES / TOTAL NO. OF OUTCOMES
{TOTAL BALLS = 12}
(1)----------> P( BLUE ) = 4 / 12 = 1/3
(2)---------> P( WHITE ) = 3 / 12 = 1/4
(3)---------->P( RED ) = 5/12
(4) --------->P(NOT WHITE) = 9/12 = 3/4
(^∇^) hope this helps dear(^▽^)
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