A bag contains 3 white balls and 2 black balls. Another bag contains 2 white and 4 black balls. A bag and a ball are picked random. The probability that the ball will be white is:
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p (white balls in first bag ) = 3÷5 =0.6
p(white balls in second bag)= 2÷4=0.5
=0.6+0.5=1.1
p(white balls in second bag)= 2÷4=0.5
=0.6+0.5=1.1
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heya there is your answer.
p(white balls)=3/5=0.6
p(white balls in another bag)=2/4=0.5
hence , the total white ball=0.6+0.5=1.1
hopes its helps u .plzz mark me as a brainliest answer.plzzzzzzz.
p(white balls)=3/5=0.6
p(white balls in another bag)=2/4=0.5
hence , the total white ball=0.6+0.5=1.1
hopes its helps u .plzz mark me as a brainliest answer.plzzzzzzz.
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