A bag contains 30 balls out of which x balls are blue. If 10 blue balls are removed from the bag, the probability of drawing a blue ball is half of the initial probability. The value of x is
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Answer: p(E2)
Step-by-step explanation: Answer:
➡️Initially there are 5 blue balls
➡️after adding 7 more balls at last bag have5+7= 12 blue balls.
Solution:
Total balls in bag = 35
Blue balls are = x
Probability of getting a blue ball p(E1) = x/35
Now 7 more blue balls are put in the box:
Total number of blue balls now = (x+7)
Total balls = 35+7= 42
Probability of getting a blue ball p(E2) =(x+7)/42
A.T.Q
2 p(E1) = p(E2)
So, there are 5 blue balls in the bag initially.
Hope it helps you.
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