A bag contains ₹ 300 in the form of 1-rupees 50paise and 25paise coins in the ratio 5:8:4 find the number of coins of each type
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Let the number of one rupee coins in a bag= 5x, 50p coins = 8x and 25 p coins = 4x
Since a bagcotains Rs.300
⇒ (1 × 5x) + (50p × 8x) + (25p × 4x) = 300
⇒ (1 × 5x) + (0.50 × 8x) + (0.25 × 4x) = 300
⇒ 5x + 4x + 1x = 300
⇒ 10x = 300
∴ x = 30
Now,
Number of one rupee coins = 5x = 5 × 30= 150
Number of one 50 coins = 8x = 8 × 30= 240
Number of one 25p coins = 4x = 4 × 30= 120
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