A bag contains 3white, 5black and 2red balls all of the same shape and size a ball is draw from the bag :find the probability that the ball draw is 1.)a black ball 2.)a red ball 3.)not a red ball
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Step-by-step explanation:
In a bag 3 balls are white
2 balls are red
5 balls are black
Total number of balls = 3 + 2 + 5 = 10
(i) Number of possible outcome of one black ball = 10
And number of favourable outcome of one black ball = 5
∴ P(E) = Number of favourable outcome/Number of all possible outcome
= 5/10 = 1/2
(ii) Number of possible outcome of one red ball = 10
And number of favourable outcome = 2
∴ P(E) = Number of favourable outcome/Number of all possible outcome
= 2/10 = 1/5
iii .Number of possible outcome = 10
Number of favourable outcome
= 3 + 5 = 8
Not a red ball
∴ P(E) = Number of favourable outcome /Number of all possible outcome
= 8/10 = 4/5
I hope this is helpful for you
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