A bag contains 4 black balls and 3 white balls balls are picked up one by one at random and placed in row. The chance that the balls are alternatively of different colour is
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Let B represent black ball and W represent White balls.
No of black ball = 4
B1, B2, B3, B4
No. of white balls = 3
W1, W2, W3
Total no. of balls = 4+3 = 7
P(getting B1) = 1/7
P(getting B2) = 1/7
P(getting B3)= 1/7
P(getting B4) = 1/7
P(getting W1) = 1/7
P(getting W2) = 1/7
P(getting W3) = 1/7
No of black ball = 4
B1, B2, B3, B4
No. of white balls = 3
W1, W2, W3
Total no. of balls = 4+3 = 7
P(getting B1) = 1/7
P(getting B2) = 1/7
P(getting B3)= 1/7
P(getting B4) = 1/7
P(getting W1) = 1/7
P(getting W2) = 1/7
P(getting W3) = 1/7
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