Question

A bag contains 4 green , 5 black and -
10 red balls a ball is drawn at random
Find the probablity that the drawn ball is
not green .​

Answer 1

Answer:

15/19

Step-by-step explanation:

n(s)=4+5+10=19

n(e)=5+10=15

so p(e)=n(e)/n(s)

=15/19

Answer 2

Answer:

bag cintains total 4+5+10 = 19 balls

probablity = black+red/total

= 15/10